Primary 5 Math :
Top Schools Exam Problems Explained

Welcome to your go-to guide for navigating Singapore Primary 5 Math! The jump to Primary 5 introduces new concepts and longer word problems, which can feel like a big adjustment for both you and your child. Take a deep breath. You are exactly in the right place.

On this page, we carefully break down actual past-year exam questions from top primary schools in Singapore. For every problem, you will see the exact working steps required to score full marks (just look for the neat blue handwriting). Below that, we provide a crystal-clear, step-by-step explanation so your child can truly grasp the underlying concepts without the tears. Let's build their confidence and conquer math together!

2025 Nanyang Primary School End-Of-Year Exam Paper 2 Q7

Ryan baked 750 cookies. He sold 50% of the cookies and gave 23 of the remaining cookies to his neighbour. He then ate some cookies and had 80 cookies left. What percentage of the cookies baked did Ryan eat?

750 ÷ 2 = 375
1 - 2/3 = 1/3
375 ÷ 3 = 125
125 - 80 = 45
45 ÷ 750 × 100% = 6%
Ans: 6%

💡 Detailed Explanation for Understanding

As the total number of cookies was given, we can work through the story step by step to find out exactly how many cookies Ryan ate.

Find the remaining cookies
Ryan baked 750 cookies and sold 50% of them. Since 50% is exactly half, we just divide by 2.
750 ÷ 2 = 375 cookies remaining.
Find the cookies left after giving them away
Ryan gave away 2 units out of 3 from the remainder. This means he was left with 1 unit out of 3 (or 1/3) of the remaining cookies.
We can find this by dividing the remainder by 3.
375 ÷ 3 = 125 cookies.
Find the number of cookies eaten
Before he ate any, he had 125 cookies. After eating some, he had 80 left. We subtract to find out how many disappeared into his tummy!
125 - 80 = 45 cookies eaten.
Find the percentage
The question asks for the percentage of the total cookies baked that he ate. We take the cookies eaten (45) divided by the total baked (750), and multiply by 100%.
45 ÷ 750 × 100% = 6%.
2025 Nanyang Primary School End-Of-Year Exam Paper 2 Q8

Charlene had $102 less than Bernice. After Charlene gave Bernice $90, Bernice had 5 times as much as what Charlene had left. How much money did Charlene have at first?

$102 + $90 + $90 = $282
5 - 1 = 4
$282 ÷ 4 = $70.50
$70.50 + $90 = $160.50
Ans: $160.50

💡 Detailed Explanation for Understanding

This is a Changed Difference Concept question. When one person gives money to another, the gap (difference) between their money changes drastically. Let's see how the gap widens!

Understand how the difference changes
At first, Bernice has $102 more than Charlene.
When Charlene gives Bernice $90, two things happen. First, Charlene's money drops by $90. Second, Bernice's money goes up by $90.
This means the gap between them widens by $90 twice!
Find the new difference
To find the new difference between their money, we add the changes to the original gap.
New difference: $102 + $90 + $90 = $282.
Use the difference in units to find 1 unit
In the end, Bernice has 5 units and Charlene has 1 unit. The difference between them is 5 - 1 = 4 units.
We know this 4-unit difference is equal to $282.
To find 1 unit (which is what Charlene has left): $282 ÷ 4 = $70.50.
Find Charlene's starting amount
In the end, Charlene has $70.50 left. Since we know she gave away $90 to Bernice earlier, we just need to add it back to find her starting amount.
$70.50 + $90 = $160.50.
2025 Nanyang Primary School End-Of-Year Exam Paper 2 Q10

There were some fruits in a crate. 49 of them were strawberries and 23 of the remainder were mangoes. The rest of them were pineapples. There were 105 more strawberries than pineapples.

(a) How many mangoes were there?

Remainder : 1 - 49 = 59

Mangoes : 23 × 59 = 1027

Pineapples : 59 - 1027 = 527

Difference : 49 - 527 = 727

1 unit : 105 ÷ 7 = 15
Mangoes : 10 × 15 = 150
Ans: 150

(b) How many fruits were there in the crate?

Total : 27 × 15 = 405
Ans: 405

💡 Detailed Explanation for Understanding

Let's solve this using the Fraction of a Remainder concept. By multiplying the fractions, we can find out exactly what fraction of the total fruits each type represents!

Solving (a):
Find the fraction for the Remainder
The whole crate is 1. Since 49 are strawberries, we subtract this from 1 to find the remainder.
1 - 49 = 59 of the total fruits.
Find the fraction for Mangoes
Mangoes are 23 of the remainder. We multiply these two fractions together.
23 × 59 = 1027 of the total fruits.
Find the fraction for Pineapples
Pineapples make up the rest of the remainder. We take the remainder fraction and subtract the mangoes.
59 - 1027 = 527 of the total fruits.
Use the clue to find 1 unit
The question tells us there were 105 more strawberries than pineapples. Let's find the difference between their fractions.
Strawberries ( 49) - Pineapples ( 527) = 727.
This means 7 units out of the total 27 units represent 105 fruits.
To find 1 unit, we divide: 105 ÷ 7 = 15.
Find the number of mangoes
We already found that Mangoes represent 1027 of the total, which means they are 10 units.
10 × 15 = 150.

Solving (b):
Find the total number of fruits
The denominator in our fractions (27) tells us there are 27 units in total.
Since 1 unit is 15, we multiply: 27 × 15 = 405.
2025 Nanyang Primary School End-Of-Year Exam Paper 2 Q13

Peter has some 20-cent coins and 50-cent coins. The number of 20-cent coins is four times as many as the number of 50-cent coins. The value of the 20-cent coins is $11.40 more than the value of the 50-cent coins.

(a) How many fewer 50-cent coins than 20-cent coins does Peter have?

(4 × $0.20) - $0.50 = $0.30
$11.40 ÷ $0.30 = 38
4 - 1 = 3
38 × 3 = 114
Ans: 114

(b) How much money does Peter have?

(4 × $0.20) + $0.50 = $1.30
38 × $1.30 = $49.40
Ans: $49.40

💡 Detailed Explanation for Understanding

Let's solve this easily using the Grouping Concept. Because the question tells us there is a "four times" relationship, we can organize these coins into identical groups to make the math simple to understand.

Solving (a):
Create a Group
Since Peter has 4 times as many 20-cent coins as 50-cent coins, we will put exactly four 20-cent coins and one 50-cent coin into every group.
Find the difference in value for ONE group
In each group, the 20-cent coins are worth more than the 50-cent coin. Value of 20-cent coins (4 × $0.20 = $0.80) minus value of the 50-cent coin ($0.50) is $0.30.
Find the total number of groups
The question tells us that in total, the 20-cent coins are worth $11.40 more than the 50-cent coins. Since every group gives us a difference of $0.30, we can figure out how many groups there are by dividing.
Total number of groups: $11.40 ÷ $0.30 = 38 groups
Find how many fewer 50-cent coins
The question asks how many fewer 50-cent coins than 20-cent coins Peter has.
In just one group, there are 4 (20-cent coins) minus 1 (50-cent coin) = 3 fewer coins.
Since there are 38 groups altogether: 38 × 3 = 114.

Solving (b):
Find the total value inside ONE group
Let's look inside one group again.
Value of the 20-cent coins ($0.80) plus the value of the 50-cent coins ($0.50) gives a total value of $1.30 for one whole group.
Find the total money Peter has
Since there are 38 groups altogether, we multiply the value of one group by 38.
38 × $1.30 = $49.40.